Free Fall Time Calculator
How long does an object take to fall from any height?
Calculate how long an object takes to fall from any height under Earth's gravity. Find fall time, final velocity, and impact dynamics for safety planning, physics problems, or engineering analysis.
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How It Works
The formula, explained simply
Imagine dropping a coin and a feather in a vacuum chamber — they hit the ground simultaneously despite their different weights. This surprising result reveals that gravity accelerates all objects equally at 9.81 meters per second squared, regardless of mass. The fall time depends only on the distance traveled and this constant acceleration.
The mathematics follows from basic kinematics. Starting from rest, an object covers distance according to the equation d = ½gt². Solving for time gives t = √(2d/g), where d is height and g is gravitational acceleration. This square root relationship explains why quadrupling the height only doubles the fall time.
Real-world deviations occur because air resistance opposes motion with a force that increases with speed. Light objects like feathers reach their terminal velocity quickly, while dense objects like ball bearings can fall hundreds of meters before air resistance matters significantly.
When To Use This
Right tool, right situation
Use this calculator for dense objects falling moderate distances where air resistance is minimal. It works well for dropped tools on construction sites, objects falling from buildings, or basic physics problem solving. The results are reliable for stones, keys, or similar compact items falling less than 100 meters.
Avoid this calculator for light objects like leaves or paper, which reach terminal velocity quickly. Don't use it for skydiving calculations beyond the first few seconds of freefall. It also doesn't apply to thrown objects with significant initial velocity or situations involving updrafts, downdrafts, or other atmospheric conditions.
The calculator is inappropriate for spacecraft reentry, high-altitude drops, or any scenario where the object approaches its terminal velocity. For safety-critical applications involving human fall protection, always consult engineering standards that account for air resistance and safety factors.
Common Mistakes
Why results sometimes look wrong
The most common error is assuming fall time increases linearly with height. Students often think a 40-meter fall takes twice as long as a 20-meter fall, when it actually takes only √2 ≈ 1.41 times longer. This misconception leads to severely underestimating impact speeds from greater heights.
Another frequent mistake is ignoring the starting velocity assumption. These equations apply only when objects start from rest. If an object is thrown downward with initial velocity v₀, the correct equation becomes t = [√(v₀² + 2gh) - v₀]/g, which reduces fall time significantly.
People also misapply vacuum results to real-world scenarios without considering air resistance. A sheet of paper dropped from 10 meters might take 3-4 seconds to fall instead of the calculated 1.43 seconds. The calculator becomes increasingly inaccurate for light objects, high altitudes, or long fall distances where terminal velocity effects dominate.
The Math
Worked examples and deeper derivation
The core equation derives from integrating constant acceleration twice. Starting with acceleration a = g downward, velocity becomes v = gt after time t, and position becomes h = ½gt² after starting from rest. Solving the position equation for time yields t = √(2h/g).
Final velocity follows directly from v = gt, substituting our time result to get v = g√(2h/g) = √(2gh). This shows final speed depends on the square root of height — doubling height increases impact speed by only 41%, not 100%. Energy conservation provides an alternative derivation: potential energy mgh converts to kinetic energy ½mv², giving the same velocity formula.
The acceleration constant g = 9.81 m/s² represents Earth's gravitational field strength at sea level. This value decreases slightly with altitude (about 0.3% at 10 km) and varies with latitude due to Earth's rotation and oblate shape, but these effects are negligible for practical calculations.
Expert Unlock
The thing most explanations skip
The vacuum assumption breaks down when drag force approaches gravitational force. For spherical objects, terminal velocity occurs when ½ρv²CdA = mg, where drag depends on air density, velocity squared, drag coefficient, and cross-sectional area. This creates a velocity ceiling that fundamentally changes the time-height relationship beyond certain thresholds.
Why does fall time increase so slowly with height?
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