Orbital Period Calculator

How long does it take to complete one full orbit?

Find out how long it takes for any object to complete one full orbit around another body. Enter the orbital radius (or altitude above surface) and the mass of the central body - see the orbital period in seconds, minutes, hours, days, or years. Assumes circular orbit and point masses.

Updated June 2026 · How this works

Worth knowing
How It Works
The formula, explained simply

Orbital mechanics follows a surprising rule: the closer you get, the faster you must move. A satellite 200 km above Earth races around at 7.8 km/s, completing an orbit in 88 minutes. Move that same satellite to geostationary height at 35,786 km altitude, and it crawls at just 3.1 km/s, taking exactly 24 hours per orbit. This isn't intuitive - we expect things farther out to move faster, like cars on a highway's outer lanes.

The orbital period calculator uses Kepler's third law, which relates orbital period to the orbital radius cubed and the central body's mass. This means doubling the orbital distance increases the period by 2.8 times (the cube root of 8). The calculation assumes perfectly circular orbits and point masses - real orbits are slightly elliptical, and bodies have finite size, but these effects are small for most practical calculations.

This tool handles any orbiting system: satellites around Earth, moons around planets, or planets around stars. The key assumption is that gravitational force dominates - this breaks down for very close orbits where tidal forces matter, or very distant orbits where other gravitational bodies interfere. For Earth satellites, the formula works accurately from about 160 km altitude up to the Moon's distance.

When To Use This
Right tool, right situation

Use this calculator when designing satellite missions, planning astronomical observations, or understanding planetary motion. Satellite operators use orbital periods to determine communication windows, coverage patterns, and station-keeping requirements. Astronomers use these calculations to predict when moons will transit in front of planets or when spacecraft will be visible from Earth.

The calculator is essential for understanding resonance effects in orbital mechanics. Many satellite constellations use specific orbital periods that create repeating ground tracks - GPS satellites, for example, orbit twice per sidereal day to maintain consistent coverage. Mission planners use period calculations to design orbits that revisit the same locations at regular intervals.

Avoid this calculator for highly elliptical orbits, where the period depends on the semi-major axis rather than the instantaneous radius. For comets, asteroid flybys, or highly eccentric satellite orbits, you need more complex orbital mechanics tools. Also avoid it for systems where non-gravitational forces dominate, such as solar sails near the Sun or low satellites experiencing significant atmospheric drag.

Common Mistakes
Why results sometimes look wrong

The most common mistake is confusing altitude with orbital radius. Altitude measures height above the surface, but orbital calculations need the distance from the center of mass. For Earth orbits, always add Earth's radius (6,371 km) to your altitude. Using altitude directly will give you orbital periods that are far too short.

Another frequent error is using incorrect mass units or forgetting scientific notation. Earth's mass is 5.972×10²⁴ kg - that's 5,972 followed by 21 zeros. Entering just 5.972 instead of 5.972e24 will give impossibly long orbital periods. Similarly, mixing metric and imperial units without conversion leads to nonsensical results.

Many people assume that orbital period calculations work for any distance, but the formula has practical limits. Very low orbits (below 160 km for Earth) experience atmospheric drag that the formula ignores. Very high orbits are influenced by other gravitational bodies - the Moon's orbit around Earth, for example, is perturbed by the Sun. The calculator assumes isolated two-body systems, which works well for most satellite and planetary calculations but fails at the extremes.

The Math
Worked examples and deeper derivation

Kepler's third law gives us the orbital period formula: T = 2π√(r³/GM), where T is the orbital period, r is the orbital radius, G is the gravitational constant (6.674×10⁻¹¹ m³/kg·s²), and M is the central body's mass. The period depends on the 3/2 power of the orbital radius - this means orbital period increases rapidly with distance.

For a concrete example, consider the International Space Station orbiting at 408 km altitude. The orbital radius is 408 + 6,371 = 6,779 km or 6,779,000 meters. Using Earth's mass of 5.972×10²⁴ kg: T = 2π√((6.779×10⁶)³/(6.674×10⁻¹¹ × 5.972×10²⁴)) = 5,565 seconds = 92.7 minutes. This matches the ISS's actual orbital period.

The formula breaks down at extreme conditions. For orbital radii smaller than about 160 km above Earth, atmospheric drag dominates and orbits decay rapidly. At distances beyond the Moon (384,400 km), the Sun's gravity begins to perturb Earth orbits significantly. For very massive central bodies or very close orbits, relativistic effects become important - GPS satellites, for example, require relativistic corrections to maintain accuracy.

International Space Station
408 km altitude above Earth (radius ~6,786 km), Earth mass 5.972×10²⁴ kg
The ISS completes one orbit in approximately 92.7 minutes, making about 15.5 orbits per day.
Geostationary Satellite
42,164 km radius from Earth center, Earth mass 5.972×10²⁴ kg
A geostationary satellite takes exactly 24 hours to orbit, staying fixed above one point on Earth's equator.
Jupiter's Moon Europa
671,034 km radius from Jupiter center, Jupiter mass 1.898×10²⁷ kg
Europa orbits Jupiter once every 3.55 Earth days, tidally locked with the same face always toward Jupiter.
Expert Unlock
The thing most explanations skip

The standard orbital period formula assumes the central body is much more massive than the orbiting object, but real systems involve two bodies orbiting their common center of mass (barycenter). For Earth-Moon calculations, this reduces the effective central mass to about 81% of Earth's mass alone. Professional orbital mechanics software accounts for this by using the reduced mass μ = G(M₁ + M₂) instead of just GM.

Why do closer orbits move faster than distant ones?

How do I calculate orbital period for satellites?
Enter the satellite's orbital radius (distance from Earth's center) and Earth's mass (5.972×10²⁴ kg). The calculator uses Kepler's third law to determine how long one complete orbit takes. Most satellites orbit between 200-2000 km above Earth's surface.
What is the difference between orbital radius and altitude?
Orbital radius measures from the center of the planet to the orbiting object. Altitude measures from the planet's surface. For Earth orbits, add 6,371 km to your altitude to get the orbital radius. This calculator requires the full orbital radius for accurate period calculations.
Why does orbital period depend on mass and distance?
Gravity pulls harder on closer objects and weaker on distant ones. Massive central bodies create stronger gravitational fields. The orbital period balances gravitational pull with centrifugal force - closer orbits need higher speeds to avoid falling inward, resulting in shorter periods.

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